# 2019 June(B02) Math Question 1

- Cost

Choice D

$$59.95\approx60$$ $$\frac{20}{100}\times60=12$$ $$60 - 12 = 48$$ $$48\approx.47.96$$

# 2019 June(B02) Math Question 2

Choice F

$$(r + b - g)(b + g) = [6 + 4 -(-9)][(4+(-9)] = 19\times(-5)= -95$$

# 2019 June(B02) Math Question 3

Choice E

$$\angle ACB = 180°- \angle ABC - \angle BAC = 180° - 108° - 42° = 30°$$ $$\angle ACD = 180° - \angle ACB = 180° - 30° = 150°$$

# 2019 June(B02) Math Question 4

Choice H

$$X=(17-10)\cdot\frac{5}{3}=\frac{35}{3}$$

# 2019 June(B02) Math Question 5

Choice C

$$9^{2}+2^{2}=C^{2}$$ $$81+4=85=C^{2}$$ $$C=\sqrt{85}$$

# 2019 June(B02) Math Question 6

Choice H

White : 10

Not-white : 3 red + 5 blue = 8

The probability of randomly selecting 1 button that is NOT white

$$= \frac{8}{10+8}=\frac{8}{18}=\frac{4}{9}$$

# 2019 June(B02) Math Question 7

Choice C

Sum of 3 consecutive odd integers

$$= 27\times3 = 81$$

# 2019 June(B02) Math Question 8

Choice K

1: 1+0=1

4: 2+2=4

6: 4+2=6

7: 5+2=7

8 is NOT a possible sum of those 2 numbers

# 2019 June(B02) Math Question 9

Choice B

$$\widetilde{13}=6.6 miles$$ $$\widetilde{23}=4.5 miles$$ $$\widetilde{25}=9.7 miles$$ $$\widetilde{12}=\widetilde{13}-\widetilde{23}=6.6-4.5=2.1 miles$$ $$\widetilde{15}=\widetilde{12}+\widetilde{25}=2.1+9.7=11.8 miles$$

# 2019 June(B02) Math Question 10

Choice H

The perimeter of the hexagon:

$$6\times10=60$$

# 2019 June(B02) Math Question 11

Choice D

N: the maximum number of bats that can be produced by the company

$$3,500+2\times N =15000$$ $$2\times N = 11500$$ $$N=5750$$

# 2019 June(B02) Math Question 12

Choice G

$$3x+2=4$$ $$\Rightarrow 3x=2$$ $$\Rightarrow x=\frac{2}{3}$$ $$2y+6=5$$ $$\Rightarrow 2y=-1$$ $$\Rightarrow y=\frac{-1}{2}$$ $$x+y=\frac{2}{3}+\frac{-1}{2}=\frac{4}{6}+\frac{-3}{6}=\frac{1}{6}$$

# 2019 June(B02) Math Question 13

Choice C

$$\require{cancel}$$ $$\frac{ 15x ^{2}+25x}{5x}=\frac{\cancel{5}(3x^{2}+5x)}{\cancel{5}x}=\frac{3x^\cancel{2}+5\cancel{x}}{\cancel{x}}=3x+5$$

# 2019 June(B02) Math Question 14

Choice K

$${\displaystyle \left\vert -5\right\vert^{2} =25}$$ $$\Rightarrow\frac{\displaystyle \left\vert -5\right\vert^{2}+(-1)}{(16\div4)\times2-5}=\frac{25-1}{4\times2-5}=\frac{24}{8-5}=\frac{24}{3}=8$$

# 2019 June(B02) Math Question 15

Choice D

This special savings account will double every 5 years.

$$\because 40\ years = 5\ years\times 8$$

Therefore, this account will double 8 times.

$$2000\times 2^{8}=2000\times256=512000$$

# 2019 June(B02) Math Question 16

Choice F

2 hours ~ 4 hours:

the number of hours the amount of water in the pond remained constant.

# 2019 June(B02) Math Question 17

Choice B

lf it rains in Franklin City on a particular day, the probability that it will rain there the following day is 0.70.

Therefore,

if it rains on a Monday,

the probability that it will NOT rain there the following day is

1 - 0.70 = 0.30

# 2019 June(B02) Math Question 18

Choice G

$$5x=9y+18$$ $$\Rightarrow 9y=5x-18$$ $$\Rightarrow y=\frac{5}{9}-2$$

# 2019 June(B02) Math Question 19

Choice B

$$Slope=\frac{y-y_{0}}{x-x_{0}}$$ $$\Rightarrow \frac{4-0}{0-2}=-2$$ $$\Rightarrow y=-2x+4$$

Choice J

# 2019 June(B02) Math Question 21

Choice D

The 1st draw: a blue …

# 2019 June(B02) Math Question 22

Choice K

At least 60 inches ⇒ …

# 2019 June(B02) Math Question 23

Choice C

$$f(x)=5-3x$$ $$\left\{-1,0,2\right\}$$ $$f(-1)=5-3(-1)=8$$ …

Choice F

# 2019 June(B02) Math Question 36

Choice K

$$\frac{9}{5}=1.8$$ $$1.\overline{8}=1.88888...$$ $$1.08=1.08$$ …

# 2019 June(B02) Math Question 37

Choice A

$$\frac{6\times3+8\times2+2\times1+4\times0}{20}$$ $$=\frac{18+16+2+0}{20}$$ $$=\frac{36}{20}$$ $$=\frac{9}{5}=1.8$$

# 2019 June(B02) Math Question 38

Choice G

$$(F)14+(\frac{-1}{40})=14-(\frac{1}{40})$$ $$(G)14-(\frac{-1}{40})=14+\frac{1}{40}$$ $$(H)14\div(\frac{-1}{40})=14\times(-40)=-560$$ $$(J)14\times(\frac{-1}{40})=\frac{-14}{40}$$ $$(K)\frac{14+\frac{-1}{40}}{2}=7+\frac{-1}{80}$$

# 2019 June(B02) Math Question 39

Choice E

$$H=0.75\times(200-A)$$

# 2019 June(B02) Math Question 40

Choice J

t=-0.0066a+15

t : degrees Celsius …

Choice C

# 2019 June(B02) Math Question 44

Choice K

$$49^{a}= (7^{2})^{a}=7$$ $$\Rightarrow a=\frac{1}{2}$$ …

Choice A

Choice B

# 2019 June(B02) Math Question 53

Choice A

$$\frac{perimeter}{4}=\frac{130+x+y}{4}$$ $$\frac{x}{\sin47°}=\frac{130}{\sin91°}=\frac{y}{\sin42°}$$ $$x=\frac{130\sin47°}{\sin91°}$$ $$y=\frac{130\sin42°}{\sin91°}$$ $$\Rightarrow\frac{perimeter}{4}=\frac{130+\frac{130\sin47°}{\sin91°}+\frac{130\sin42°}{\sin91°}}{4}$$

Choice G

# 2019 June(B02) Math Question 59

Choice A

Definition of y-intercept: the y-coordinate …

Choice K