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  • 2019 June(B02) Math Question 3

    Angles

    - Collinear Points & Triangles

    Choice E
    $$\angle ACB = 180°- \angle ABC - \angle BAC = 180° - 108° - 42° = 30°$$ $$\angle ACD = 180° - \angle ACB = 180° - 30° = 150°$$

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