**Choice C**

The number of members who are not officers is 32-5=27.

Luis is one of the 27 members who are not officers. Therefore the probability that he will be chosen is\(\frac{1}{27}\).

**Choice K**

Since the two triangles are congruent. The following must be true: $$\angle A\cong\angle D\\$$ $$\angle B\cong\angle E \\$$ $$\angle C\cong\angle F\\$$ $$\overline{AB}\cong\overline{DE}\\$$ $$\overline{BC}\cong\overline{EF}\\$$ $$\overline{AC}\cong\overline{DF} $$

**Choice C**

$$\angle BCD+\angle BCA = 180°$$ $$\Rightarrow\angle BCA=180°-100°=80°$$ $$\angle CAB+\angle ABC+\angle BCA=180°$$ $$\Rightarrow 65°+X°+80°=180°$$ $$\Rightarrow X°=35°$$

**Choice E**

$$ \begin{align} 2|2-9|-3(4+2) & = 2|-7|-3(6) \\ & = 2\cdot7-3\cdot6 \\ & = 14-18 \\ & = -4 \end{align} $$

**Choice G**

$$ \left\{ \begin{aligned} -2x+y &=2 \\ x+y&=5 \end{aligned} \right. \ \ \Rightarrow\ \ \left\{ \begin{aligned} x &=1 \\ y&=4 \end{aligned} \right. \ \ \Rightarrow\ \ Point \ of\ intersection\ is\ (1,4) $$

**Choice C**

$$Assessed\ value=$56,000 \times \frac{3}{4}=$42,000\\$$ $$\Rightarrow Yearly\ tax=$3 \times\frac{$42,000}{$100}=$1,260$$

**Choice C**

Let the number of month be m. $$$75+$65\cdot m=$495\\ \Rightarrow m = 6.46\approx7$$

**Choice F**

$$Slope\ of\ \overleftrightarrow{HM} = \frac{y_2-y_1}{x_2-x_1} =\frac{-4-2}{2-(-2)} =\frac{-6}{4}=-\frac{3}{2}$$

**Choice B**

The questions asks what the ( ? ) should be in: $$45x^2+26x-8=(5x+4)(\quad?\quad)$$ To solve for the ( ? ), we need to perform the following: $$ \begin{pmatrix}5&4\\\color{red}{\frac{45}{5}}&\color{red}{\frac{-8}{4}}\\ \end{pmatrix} \Rightarrow \begin{pmatrix}5&4\\\color{red}{9}&\color{red}{-2}\\ \end{pmatrix}\\$$ $$\Rightarrow (\quad?\quad) = (9x-2)$$

**Choice H**

We know that $$sin^2x\ + cos^2x=1\\$$ $$\Rightarrow cos^2x=1-sin^2x=1-\frac{4}{13}=\frac{9}{13}$$

**Choice E**

Let each side of small squares be k:

Area of rectangle region = $$6k\cdot8k=1\Rightarrow k^2=\frac{1}{6\cdot8}$$

Therefore, area of shaded region = $$7k\cdot5k = 7\cdot5\cdot k^2=\frac{7\cdot5}{8\cdot6}$$

**Choice J**

It is given that \(\overline{AB} \cong \overline{AC}\), thus \(\angle B =\angle C\).

Because \(\angle A+\angle B +\angle C = 180^\circ;\ \angle A=48^\circ\), we have: \(\angle C = \frac{180^\circ-48^\circ}{2}=66^\circ\)

**Choice B**

It is given that $$a_5=39$$. All you need to do is plug in 6 for n: $$\begin{align} a_6 & =a_5+(6-1)^2\\ &=39+25\\ &=64 \end{align}$$

**Choice G**

Because the line is parallel to the line represented by y = -2x - 4, the line has the same slope -2. Thus we can write the line as: $$y = -2x + b$$ Because the line passes through (0,7): $$7=-2\cdot0 +b\\$$ $$\Rightarrow b=7\\$$ Therefore, the line is: $$y = -2x + 7$$

**Choice D**

The bedroom floor can be seen as being consisting of one rectangle and a square with lengths as below: Thus the area is $$5\times5+6\times9=79$$. The number of tiles needed is $$\frac{79\ ft^2}{1 \ ft^2}=79$$

**Choice F**

We are told that the survey accurately predict how the 1,200 resident would respond: $$\require{cancel}\frac {x}{1200}=\frac {12}{60}\\$$ $$\Rightarrow x=\frac {12\times\cancel{1200}20}{\cancel{60}}=240 $$

**Choice A**

We are told that the …

**Choice G**

$$(a^2)^u=a^{12 …

**Choice B**

The shifting rule is that …

**Choice F**

$$x=\frac{4a+b}{3 …

**Choice B**

Let the length of the …

**Choice J**

We need to know \(\pi …

**Choice A**

Area of rectangle =$$3\sqrt5 …

**Choice H**

11 either divided or multiplied …

**Choice D**

And, by rearranging the expression …

**Choice E**

The key of the committee …

**Choice E**

To rewrite the expression, we …

**Choice F**

We need to know: $$1 …

**Choice D**

In a square, the lengths …

**Choice K**

In the right triangle \( \Delta …

**Choice B**

The length of BC can …

**Choice F**

The volume of the layer …

**Choice E**

The net profit per batch …

**Choice J**

The workings are as follows …

**Choice C**

The fence is indicated by …

**Choice G**

$$ Area \ of\ garden = 25 \cdot …

**Choice B**

The number of bulbs in …

**Choice J**

The amplitude of the function …

**Choice B**

You can substitute the value …

**Choice J**

The median would be the …

**Choice D**

Because the absolute value equation …

**Choice F**

All we need to do …

**Choice B**

The circumference ofthe circle = 2πr …

**Choice F**

The question is asking for …

**Choice D**

$$ \begin{align} Area \ of\Delta …

**Choice F**

The decimal repeats in chunks …

**Choice C**

As can be seen in …

**Choice J**

The vertical asymptote \(x=3 …

**Choice C**

The confirmation number will be …

**Choice K**

The range of values can …

**Choice C**

For a matrix A = \(\begin …

**Choice G**

The identification code will be …

**Choice D**

The complex plane is shown …

**Choice F**

To make f(x) as …

**Choice A**

You don’t have to …

**Choice K**

The coordinates of the center …