The identification code will be in the following format: $$\underset{―}{Digi{t}_1}\underset{―}{Lette{r}_1}\underset{―}{Lette{r}_2}\underset{―}{Lette{r}_3}\underset{―}{Lette{r}_4}\underset{―}{Digi{t}_2}$$ $\underset{―}{Digi{t}_1}$ and$\underset{―}{Digi{t}_2}$ can be any digits from 0-9, while the letters can not be repeated from the 26 English alphabet. Thus the total number of possible codes is: $$10\cdot (26)\cdot (26)\cdot (25)\cdot (24)\cdot (23)\cdot 10$$ of which the number of codes with the fixed letters "MATH" $$\underset{―}{Digi{t}_1}\underset{―}{M}\underset{―}{A}\underset{―}{T}\underset{―}{H}\underset{―}{Digi{t}_2}$$ is $$10\cdot 10$$ Therefore, the probability of randomly selecting such a code is: $$\frac{10\cdot 10}{10\cdot (26)\cdot (26)\cdot (25)\cdot (24)\cdot (23)\cdot 10}$$