• Choice K

    $$ 1st\ birthday\ deposit=\$ 500 $$

    $$ 2nd\ birthday\ deposit=\$ 500+\$200=\$700 $$

    Similarly deposit will be increased by $200 for every upcoming birthday. We have to find the deposits of all 6th birthdays.

    $$ \therefore \ 6th \ birthday\ deposit=\$ 500+\$1000=\$1500 $$

    And

    $$ Total\ amount\ of\ money\ deposited=\frac{500+1500}{2}\times6=\$6000 $$

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