• Choice J

    Given that

    a{10}=30a_\{10\}=30 x=10x=10 d=2d=2

    so,

    a{n}=a1+d(x1)a_\{n\}=a_1+d(x-1) 30=a1+2(101)30=a_1+2(10-1) 30=a1+1830=a_1+18 a1=12\therefore a_1=12

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