- Choice J
$(x+5)(x-\frac{3}{4})=0$
$=> (x+5)(x-\frac{3}{4})\times4=0$
$=> (x+5)(4x-3)=0$
$=> 4x^2-3x+5\times4x-5\times3=0$
$=> 4x^2+17x-15=0$
$=> 4x^2+17x-15=y$
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$(x+5)(x-\frac{3}{4})=0$
$=> (x+5)(x-\frac{3}{4})\times4=0$
$=> (x+5)(4x-3)=0$
$=> 4x^2-3x+5\times4x-5\times3=0$
$=> 4x^2+17x-15=0$
$=> 4x^2+17x-15=y$
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