- Choice J
$1-(\frac{3}{8}+\frac{1}{4}+\frac{1}{8}+\frac{1}{12}+\frac{1}{16}+\frac{1}{24})=\frac{1}{16}$
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$1-(\frac{3}{8}+\frac{1}{4}+\frac{1}{8}+\frac{1}{12}+\frac{1}{16}+\frac{1}{24})=\frac{1}{16}$
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