- Choice G
$$a > 0 ⇒ -a <0 $$
$$b < 0 ⇒ b^2 > 0 $$
Therefore the point is (-,+) and should be in the II quadrant.
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$$a > 0 ⇒ -a <0 $$
$$b < 0 ⇒ b^2 > 0 $$
Therefore the point is (-,+) and should be in the II quadrant.
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