ACT 2016 April(73E) Math Question 16 Explanation - ACT Helper

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2016 April(73E) Math Question 16
Statistics
- Mean, Median
Choice J
$M e a n o f t h e f i r s t 4 p r o j e c t s = \frac{70 + 75 + 85 + 94}{4} = 81$ $M e a n o f t h e 5 p r o j e c t s = \frac{70 + 75 + 85 + 94 + x}{5} \geq 81 + 2 = 83$ $\Rightarrow x \geq 91$
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