ACT 2012 December(71A) Math Question 20 Explanation - ACT Helper

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2012 December(71A) Math Question 20
Statistics
- Mean, Median
Choice K
$160 + 1006 + 104 + 113 + 160 + 103 + 161 + 89 + 96 = 1092$ $\Rightarrow \frac{1092 + x + y}{9 + 2} = \frac{1092 + x + y}{11}$
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