2026 February(Z14) Math Question 40
Algebraic & Function Expressions
- Simplify Algebraic Expressions
y−1y+1−2(y−1)4y+4\frac{y-1}{y+1} - \frac{2(y-1)}{4y+4}y+1y−1−4y+42(y−1)
Note 4y+4=4(y+1)4y + 4 = 4(y+1)4y+4=4(y+1):
=y−1y+1−2(y−1)4(y+1)=y−1y+1−y−12(y+1)= \frac{y-1}{y+1} - \frac{2(y-1)}{4(y+1)} = \frac{y-1}{y+1} - \frac{y-1}{2(y+1)}=y+1y−1−4(y+1)2(y−1)=y+1y−1−2(y+1)y−1
=2(y−1)−(y−1)2(y+1)=y−12(y+1)= \frac{2(y-1) - (y-1)}{2(y+1)} = \frac{y-1}{2(y+1)}=2(y+1)2(y−1)−(y−1)=2(y+1)y−1
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