35 February(Z14) Math Question 35
Probability
- Combinations
Choose 5 chairs for 4 people where order matters (permutation):
P(5,4)=5!(5−4)!=5!1!=5×4×3×2=120P(5,4) = \frac{5!}{(5-4)!} = \frac{5!}{1!} = 5 \times 4 \times 3 \times 2 = 120P(5,4)=(5−4)!5!=1!5!=5×4×3×2=120
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