35 February(Z14) Math Question 20
Quadratic Equations
- FOIL
(3x−1)(2x−5)=6x2−15x−2x+5=6x2−17x+5(3x - 1)(2x - 5) = 6x^2 - 15x - 2x + 5 = 6x^2 - 17x + 5(3x−1)(2x−5)=6x2−15x−2x+5=6x2−17x+5
So a=6a = 6a=6, b=−17b = -17b=−17, c=5c = 5c=5.
a+b+c=6−17+5=−6a + b + c = 6 - 17 + 5 = -6a+b+c=6−17+5=−6
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