35 February(Z14) Math Question 2
Algebraic & Function Expressions
- Solve Function Expressions
f(2,3)=3(2)2−2(3)=3(4)−6=12−6=6f(2,3) = 3(2)^2 - 2(3) = 3(4) - 6 = 12 - 6 = 6f(2,3)=3(2)2−2(3)=3(4)−6=12−6=6
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