35 February(Z14) Math Question 12
Quadratic Equations
- solve-quadratic-equations
2x2+5x=32x^2 + 5x = 32x2+5x=3 2x2+5x−3=02x^2 + 5x - 3 = 02x2+5x−3=0 (2x−1)(x+3)=0(2x - 1)(x + 3) = 0(2x−1)(x+3)=0 x=12 or x=−3x = \frac{1}{2} \text{ or } x = -3x=21 or x=−3
Since x>0x > 0x>0: x=12x = \frac{1}{2}x=21.
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