Given that

$$ \iota = \sqrt{-1} $$

$$ \frac{\iota + \iota^4+\iota^3}{\iota^3 + \iota^4+\iota^5}=? $$

As we know that

$$ \iota^2=-1,\ \iota^4=1,\ \iota^3=-\iota $$

So,

$$ \therefore \frac{\iota + \iota^4+\iota^3}{\iota^3 + \iota^4+\iota^5}=\frac{\iota -1-\iota}{-\iota + 1+\iota}=-\frac{1}{1} $$

$$ =-1 $$