• Choice D

    As given point M=(2a,5b). When point Q is at (4a,0):

    Slope={y2y1}{x2x1}Slope=\frac\{y_2-y_1\}\{x_2-x_1\}
    Slope={05b}{4a2a}={5b}{2a}=2.5Slope=\frac\{0-5b\}\{4a-2a\}=-\frac\{5b\}\{2a\}=-2.5

    Similarly when point Q=(5a,0), then

    Slope={05b}{5a2a}={5b}{3a}=1.6Slope=\frac\{0-5b\}\{5a-2a\}=-\frac\{5b\}\{3a\}=-1.6

    So it is clear that the slope will increase but never be positive.

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