• 2021 April(Z04) Math Question 47

    Probability

    - Combinations

    Permutations
    Choice D
    nPr={n!}{(n−r)!}_nP_r=\frac\{n!\}\{(n-r)!\}
    6P3={6!}{(6−3)!}=6×5×4=120_6P_3=\frac\{6!\}\{(6-3)!\}=6\times 5 \times 4 =120

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