$$P(thespacecapsulewilllandinwater)=\frac{Areaofwater}{AreaofEart{h}^{\prime }sSurface}\times 100\mathrm{\%}$$

$$=\frac{3.63\times {10}^8}{3.63\times {10}^8+1.48\times {10}^8}\times 100\mathrm{\%}$$

$$\approx 71\mathrm{\%}$$