Volume of one brick: $V = 3.5 \times 2.75 \times 8.5 = 81.8125 \text{ in}^3$

Weight of one brick: $81.8125 \times 0.06 \approx 4.909 \text{ lb}$

Maximum number of bricks under the $950$-lb limit: $\frac{950}{4.909} \approx 193.5 \Rightarrow 193 \text{ bricks}$