2024 December(H31) Math Question 32
Algebraic & Function Expressions
- Solve Function Expressions
We have f(x)=x+2f(x) = x + 2f(x)=x+2 and g(x)=1x2g(x) = \dfrac{1}{x^2}g(x)=x21.
The composition g(f(x))g(f(x))g(f(x)) means we substitute f(x)f(x)f(x) into ggg:
g(f(x))=g(x+2)=1(x+2)2g(f(x)) = g(x + 2) = \frac{1}{(x + 2)^2}g(f(x))=g(x+2)=(x+2)21
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