2024 December(H31) Math Question 25
Trigonometry
- Pythagorean Theorem & sin cos tan
Use the Pythagorean identity: sin2θ+cos2θ=1\sin^2\theta + \cos^2\theta = 1sin2θ+cos2θ=1 for any angle θ\thetaθ.
Substituting 2θ2\theta2θ for θ\thetaθ:
sin2(2θ)+cos2(2θ)=1\sin^2(2\theta) + \cos^2(2\theta) = 1sin2(2θ)+cos2(2θ)=1
Therefore:
3[sin2(2θ)+cos2(2θ)]=3(1)=33[\sin^2(2\theta) + \cos^2(2\theta)] = 3(1) = 33[sin2(2θ)+cos2(2θ)]=3(1)=3
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