• Choice D

    Use the Pythagorean identity: sin2θ+cos2θ=1\sin^2\theta + \cos^2\theta = 1 for any angle θ\theta.

    Substituting 2θ2\theta for θ\theta:

    sin2(2θ)+cos2(2θ)=1\sin^2(2\theta) + \cos^2(2\theta) = 1

    Therefore:

    3[sin2(2θ)+cos2(2θ)]=3(1)=33[\sin^2(2\theta) + \cos^2(2\theta)] = 3(1) = 3

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