2024 December(H31) Math Question 24
Perimeter, Area, Volume
- Other Shapes
The volume of a cone is:
V=13πr2hV = \frac{1}{3}\pi r^2 hV=31πr2h
Substitute V=616V = 616V=616 and h=5h = 5h=5:
616=13πr2(5)616 = \frac{1}{3}\pi r^2 (5)616=31πr2(5)
616=5πr23616 = \frac{5\pi r^2}{3}616=35πr2
Solve for r2r^2r2:
r2=616×35π=1,8485πr^2 = \frac{616 \times 3}{5\pi} = \frac{1,848}{5\pi}r2=5π616×3=5π1,848
Take the square root:
r=616(3)5πr = \sqrt{\frac{616(3)}{5\pi}}r=5π616(3)
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