2024 September(H11) Math Question 34
Number Types & Properties
- Complex Number
Expand each term using i2=−1i^2 = -1i2=−1:
First term: −2i(3+4i)-2i(3 + 4i)−2i(3+4i)
=−6i−8i2=−6i−8(−1)=−6i+8=8−6i= -6i - 8i^2 = -6i - 8(-1) = -6i + 8 = 8 - 6i=−6i−8i2=−6i−8(−1)=−6i+8=8−6i
Second term: −3(2+5i)-3(2 + 5i)−3(2+5i)
=−6−15i= -6 - 15i=−6−15i
Combine:
=(8−6i)+(−6−15i)= (8 - 6i) + (-6 - 15i)=(8−6i)+(−6−15i)
=(8−6)+(−6−15)i= (8 - 6) + (-6 - 15)i=(8−6)+(−6−15)i
=2−21i= 2 - 21i=2−21i
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