• Choice K

    In a right triangle, if sinθ=ab\sin\theta = \frac{a}{b} and tanθ=ac\tan\theta = \frac{a}{c}, identify the sides:

    sinθ=oppositehypotenuse=ab    opposite=a,  hypotenuse=b\sin\theta = \frac{\text{opposite}}{\text{hypotenuse}} = \frac{a}{b} \implies \text{opposite} = a, \; \text{hypotenuse} = b

    tanθ=oppositeadjacent=ac    adjacent=c\tan\theta = \frac{\text{opposite}}{\text{adjacent}} = \frac{a}{c} \implies \text{adjacent} = c

    Therefore:

    cosθ=adjacenthypotenuse=cb\cos\theta = \frac{\text{adjacent}}{\text{hypotenuse}} = \frac{c}{b}

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