• Choice D

    The expected value is:

    E(X)=1213+k23=20E(X) = 12 \cdot \frac{1}{3} + k \cdot \frac{2}{3} = 20

    4+2k3=204 + \frac{2k}{3} = 20

    2k3=16\frac{2k}{3} = 16

    k=24k = 24

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