Set up the system of equations where $n$ = cost of a notebook and $p$ = cost of a pen:

$2n + p = 7$ $3n + 2p = 11$

From the first equation: $p = 7 - 2n$.

Substitute into the second:

$3n + 2(7 - 2n) = 11$ $3n + 14 - 4n = 11$ $-n = -3$ $n = 3, \quad p = 7 - 2(3) = 1$

One notebook and one pen:

$n + p = 3 + 1 = \$4.00$