2023 April(F11) Math Question 24
Trigonometry
- Pythagorean Theorem & sin cos tan
Given sinA=2425\sin A = \frac{24}{25}sinA=2524, the opposite side =24= 24=24 and hypotenuse =25= 25=25.
Adjacent side =252−242=625−576=49=7= \sqrt{25^2 - 24^2} = \sqrt{625 - 576} = \sqrt{49} = 7=252−242=625−576=49=7.
tanA=247\tan A = \frac{24}{7}tanA=724
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