• Choice J

    $$ Total\ cars=16 $$

    where

    $$ mimivans=6,\ sedans=7\ and\ hatchbacks=3 $$

    Thalia will rent 3 cars chosen randomly. So the number of combinations of selected cars is

    $$ ^{16}C_3=\frac{16\times15\times14}{3\times2\times1}=8\times5\times14 $$

    The number of combinations of renting 1 of each of the 3 types of cars is

    $$ 6\times7\times3 $$

    $$ \therefore Probability=\frac{6\times7\times3}{8\times5\times14}=\frac{9}{40} $$

    So choice J is correct.

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