$$x^{\frac{1}{4}}.x^{\frac{1}{6}}=?$$

$$x^{\frac{1}{4}}.x^{\frac{1}{6}}=x^{\frac{1}{4}+\frac{1}{6}}$$

$$=x^{\frac{3+2}{12}}$$

$$=x^{\frac{5}{12}}$$

$$=(x^5{)}^{\frac{1}{12}}$$

$$=\sqrt[12]{x^5}$$