- Choice E
Given that
$$ \iota^2=\sqrt{-1} $$
then
$$ (3+b\iota)(3-b\iota)=9-b^2\iota^2 $$
$$ =9+b^2 $$
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Given that
$$ \iota^2=\sqrt{-1} $$
then
$$ (3+b\iota)(3-b\iota)=9-b^2\iota^2 $$
$$ =9+b^2 $$
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