- Choice A
$$ Base =AC = 4-(-2)=6 $$

$$ Height = Distance\ from\ B\ to\ AC = 2-(-1)=3 $$

$$ \therefore Area\ of\ \triangle ABC=\frac{Base\times Height}{2}=\frac{6\times 3}{2}=9 $$

## Skills you are tested for:

Was this explanation helpful?

- Choice A
$$ Base =AC = 4-(-2)=6 $$

$$ Height = Distance\ from\ B\ to\ AC = 2-(-1)=3 $$

$$ \therefore Area\ of\ \triangle ABC=\frac{Base\times Height}{2}=\frac{6\times 3}{2}=9 $$

## Skills you are tested for:

Was this explanation helpful?

## Comments