• Choice A
    Base=AC=4(2)=6Base =AC = 4-(-2)=6
    Height=Distance  from  B  to  AC=2(1)=3Height = Distance\; from\; B\; to\; AC = 2-(-1)=3
    Area  of  ABC={Base×Height}{2}={6×3}{2}=9\therefore Area\; of\; \triangle ABC=\frac\{Base\times Height\}\{2\}=\frac\{6\times 3\}\{2\}=9

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