- Sum of angles of a triangleChoice D
$$ \angle B=90^o $$
$$ \angle A=150^o-114^o=36^o $$
$$ \therefore \angle C=180^o-90^o-36^o=54^o $$
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$$ \angle B=90^o $$
$$ \angle A=150^o-114^o=36^o $$
$$ \therefore \angle C=180^o-90^o-36^o=54^o $$
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