Given that

$$f(x)=x^2+7x-3andg(x)=x^2-4x+5$$

and

$$h(x)=f(x)-g(x)$$

So

$$h(x)=x^2+7x-3-(x^2-4x+5)$$

$$h(x)=11x-8$$

$$\therefore h(2)=11(2)-8=14$$