• 2021 December(E23) Math Question 37

    Trigonometry

    - Pythagorean Theorem & sin cos tan

    Pythagorean Theorem and Special Right Triangles
    Choice B
    EF=20cmEF=20cm
    ∠EDF=30o\angle EDF=30^o
    ∠DEF=90o\angle DEF=90^o
    Lengh  of  EG=?Lengh\; of\; EG=?

    As EF=20cm so by applying the ratios of triangles having angles 30, 60 and 90 degrees, we can see that

    Lengh  of  ED=203Lengh\; of\; ED=20\sqrt 3
    ∴Lengh  of  EG={203}{2}=103\therefore Lengh\; of\; EG=\frac\{20\sqrt 3\}\{2\}=10\sqrt 3

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