- Algebraic ProblemsChoice J
$$ Cost\ of\ 3\ apples\ and\ 4\ oranges=\$ 3.47 $$
$$ Cost\ of\ 12\ oranges=\$ 6.36 $$
$$ Total\ amount=\$10 $$
$$ Cost\ of\ 1\ orange=\frac{6.36}{12}=\$0.53 $$
$$ Cost\ of\ 4\ orange=4\times 0.53=\$2.12 $$
$$ Cost\ of\ 3\ apples=\$3.47-\$2.12=\$1.35 $$
$$ Cost\ of\ 1\ apples=\frac{1.35}{3}=\$0.45 $$
So the number of apples she can buy today is
$$ Apples=\frac{10}{0.45}=22.22\approx 22 $$
Skills you are tested for:
Was this explanation helpful?
Comments