- Pythagorean Theorem and Special Right Triangles, Speed, Distance, and TimeChoice H
$$ Distance =\sqrt{40^2+30^2}=50 $$
$$ Time = \frac{{Distance}}{{Speed}}=\frac{50}{50}=1 $$
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$$ Distance =\sqrt{40^2+30^2}=50 $$
$$ Time = \frac{{Distance}}{{Speed}}=\frac{50}{50}=1 $$
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