2021 April(D05) Math Question 10
Perimeter, Area, Volume
- Triangles, Squares, Rectangles, Circles
LengthB=34×LengthA=34×64Length_B=\frac{3}{4}\times Length_A=\frac{3}{4}\times 64LengthB=43×LengthA=43×64
WidthB=34×WidthA=34×48Width_B=\frac{3}{4}\times Width_A=\frac{3}{4}\times 48WidthB=43×WidthA=43×48
LengthC=34×LengthB=34×34×64=36Length_C=\frac{3}{4}\times Length_B=\frac{3}{4}\times\frac{3}{4}\times 64=36LengthC=43×LengthB=43×43×64=36
WidthC=34×WidthB=34×34×48=27Width_C=\frac{3}{4}\times Width_B=\frac{3}{4}\times \frac{3}{4}\times 48=27WidthC=43×WidthB=43×43×48=27
∴PerimeterC=2×(LengthC+WidthC)=2×(37+26)=126\therefore Perimeter_C=2\times(Length_C+Width_C)=2\times(37+26)=126∴PerimeterC=2×(LengthC+WidthC)=2×(37+26)=126
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