• 2020 December(D03) Math Question 5

    Probability

    - One Event

    Probability
    Choice A
    Number  of  juniors=9Number\; of\; juniors=9
    Number  of  seniors=11Number\; of\; seniors=11

    As 1 senior is selected, so the number of seniors available for selection is

    Number  of  seniors=11−1=10Number\; of\; seniors=11-1=10
    Total  number  of  members  available=10+9=19Total\; number\; of \; members \; available=10+9=19

    We have to find the probability of selecting a junior out of the remaining seniors and juniors:

    Probability  of  selecting  a  junior={Number  of  juniors}{Total  number  of  members  available}={9}{19}Probability\; of\; selecting\; a\; junior=\frac\{Number\; of\; juniors\}\{Total\; number\; of \; members \; available\}=\frac\{9\}\{19\}

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