ACT 2018 December(B05) Math Question 19 Explanation - ACT Helper

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2018 December(B05) Math Question 19
Algebraic & Function Expressions
- Solve Algebraic Expressions
Choice C
$x = - 1, y = 2,$ $x^{3} - 2 x^{2} y - 4 x y^{2} + 8$ $= (- 1)^{3} - 2 (- 1)^{2} \times 2 - 4 (- 1) \times 2^{2} + 8$ $= - 1 - 2 \times 2 + 4 \times 4 + 8$ $= - 1 - 4 + 16 + 8$ $= 19$
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