ME = AM – AE = AM – BN = 5 – 1 = 4;

MN = 8

⇒ AB = CD = EN = √(ME² + MN²) = 4√3

arc AMD = 2/3 ⋅ 2π ⋅ 5 = 20/3 ⋅ π

arc BNC = 1/3 ⋅ 2π ⋅ 1 = 2/3 ⋅ π

⇒ Length of the belt = arc AMD + AB + arc BNC + CD = 20/3 ⋅ π + 4√3 + 2/3 ⋅ π + 4√3 = 22/3 ⋅ π + 8√3