ACT 2011 June(69F) Math Question 16 Explanation - ACT Helper

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2011 June(69F) Math Question 16
Absolute Values
- Absolute Value Expressions
Choice F
$f (- 1) =∣ - 1 ∣^{3} - 1 = 1^{3} - 1 = 1 - 1 = 0$
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