ACT 2010 June(68C) Math Question 1 Explanation - ACT Helper

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2010 June(68C) Math Question 1
Probability
- One Event
Choice C
$B l u e = \frac{1}{4} = \frac{6}{24}$ $P u r p l e = \frac{1}{8} = \frac{3}{24}$ $G r e e n = \frac{1}{12} = \frac{2}{24}$ $O r a n g e = \frac{3}{8} = \frac{9}{24}$ $R e d = \frac{1}{6} = \frac{4}{24}$
The chance of stopping in green is the lowest.
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