ACT 2009 December(68A) Math Question 6 Explanation - ACT Helper

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2009 December(68A) Math Question 6
Algebraic & Function Expressions
- Systems of Equations
Choice J
$3 p i e c e s = x, y, z$ $x = 2 y = 2 (2 z) = 4 z$ $y = 2 z$ $\Rightarrow x + y + z = 4 z + 2 z + z = 21$ $\Rightarrow 7 z = 21$ $\Rightarrow z = 3$ $x = 4 z = 12$
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