- Choice A
To maximize the value of x, you must minimize the value of

$$y^{2}$$ $$y^{2}=0,\ x^{2}=256$$ $$x=\pm\sqrt{256}=\pm16$$The positive 16 is the answer.

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- Choice A
To maximize the value of x, you must minimize the value of

$$y^{2}$$ $$y^{2}=0,\ x^{2}=256$$ $$x=\pm\sqrt{256}=\pm16$$The positive 16 is the answer.

## Skills you are tested for:

Was this explanation helpful?

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