• Choice F
    $$x^{2}-2x+n=0$$ $$x=4,$$ $$\Rightarrow 4^{2}-2\cdot4+n=0$$ $$\Rightarrow 16-8+n=0$$ $$\Rightarrow n=-8$$ $$x=-2,$$ $$\Rightarrow (-2)^{2}-2(-2)+n=0$$ $$\Rightarrow 4+4+n=0$$ $$\Rightarrow n=-8$$

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