# 2015 June(73C) Math Question 1 Choice C

$$a(4-a)-5(a+7)=4a-a^2-5a-35=-a^2-a-35$$

# 2015 June(73C) Math Question 2 Choice G

$$\frac{1}{4}=0.25 \\$$ $$\Rightarrow 0.03 \leq 0.2 \leq 0.25 \\$$ $$\Rightarrow 0.03 \leq 0.2 \leq \frac{1}{4}$$

# 2015 June(73C) Math Question 3 Choice C

$$x^2=29-4=25 \\$$ $$\Rightarrow x^2-4=25-4=21$$

# 2015 June(73C) Math Question 4 Choice H

Since T and U bisect QR and QS, respectively, TU//RS. Thus, $$\angle TUQ=\angle S=60° \\$$ $$\Rightarrow \angle TUS=180°-\angle TUQ=180°-60°=120°$$

# 2015 June(73C) Math Question 5 Choice C The line is going downwards. Therefore the slope is negative.

# 2015 June(73C) Math Question 6 Choice K

$$\sqrt{81}=9 \\$$ $$\sqrt{99}\approx\sqrt{100}=10$$ $$\\ 9 \leq 9.2371 \leq 10 \\$$ $$\Rightarrow 81\leq the \ number \leq 99$$

# 2015 June(73C) Math Question 7 Choice E

$$p=\frac{10-2}{10}=\frac{4}{5}$$

# 2015 June(73C) Math Question 8 Choice K

$$\frac{x_{A}+(-3)}{2}=1 \\$$ $$\Rightarrow x_{A}=5 \\$$ $$\frac{y_{A}+4}{2}=2 \\$$ $$\Rightarrow y_{A}=0$$

# 2015 June(73C) Math Question 9 Choice B

$$2x+8=116 \\$$ $$\Rightarrow x=54$$

# 2015 June(73C) Math Question 10 Choice H

$$500+200x=2,200 \\$$ $$\Rightarrow x=8.50$$

# 2015 June(73C) Math Question 11 Choice D

$$(3x+6)(2x-1)=6x^2-3x+12x-6=6x^2+9x-6$$

# 2015 June(73C) Math Question 12 Choice J

A box of 25 candies at Tamika's Treat costs $4.25. Thus the money left is$10.00 - $4.25 =$5.75, which is 23 quarters: $$\frac{5.75}{0.25}=23$$

# 2015 June(73C) Math Question 13 Choice B

$$\frac{3.75}{20}=0.1875\approx 0.19$$

# 2015 June(73C) Math Question 14 Choice F

Only the equation in F fulfils all the given prices and the number of candies given in the table.

# 2015 June(73C) Math Question 15 Choice E

The opposite of 'at least 1' is 'no one'.

# 2015 June(73C) Math Question 16 Choice J # 2015 June(73C) Math Question 17 Choice E

$$\frac{9\times9\times12}{3\times3\times3}=36$$

# 2015 June(73C) Math Question 18 Choice J

$$f(-4)=-4(-4)^{3}-4(-4)^{2} =-4(-64)-4(16) =256-64 =192$$

# 2015 June(73C) Math Question 19 Choice A

$$x+2y=4 \\$$ $$-2x+y=7 \\$$ $$\Rightarrow x=-2, \ y=3$$

# 2015 June(73C) Math Question 20 Choice G $$x=\sqrt{8^2+9^2}\approx12 \\$$ $$Perimeter = 8+10+12+19=49\approx50$$

# 2015 June(73C) Math Question 21 Choice C

$$5\times7-4\times6=11$$

# 2015 June(73C) Math Question 22 Choice H

# 2015 June(73C) Math Question 29 Choice A

# 2015 June(73C) Math Question 31 Choice B

# 2015 June(73C) Math Question 33 Choice B

$$\frac{3.6}{12}=30 \%$$

# 2015 June(73C) Math Question 34 Choice F # 2015 June(73C) Math Question 36 Choice H

12 - 3.6 = 8.4

# 2015 June(73C) Math Question 37 Choice A

4 - 1 = 3

# 2015 June(73C) Math Question 38 Choice J

# 2015 June(73C) Math Question 41 Choice D

The median will be the …

# 2015 June(73C) Math Question 42 Choice H

# 2015 June(73C) Math Question 44 Choice G

0.05 fits the data …

# 2015 June(73C) Math Question 45 Choice A

# 2015 June(73C) Math Question 47 Choice E

# 2015 June(73C) Math Question 50 Choice F # 2015 June(73C) Math Question 53 Choice E Since the given equation is …

# 2015 June(73C) Math Question 54 Choice J

The slopes of two lines …

# 2015 June(73C) Math Question 55 Choice A

The shaded area lies below …

# 2015 June(73C) Math Question 56 Choice K

# 2015 June(73C) Math Question 59 Choice D

The asymptote of a function …

# 2015 June(73C) Math Question 60 Choice F Conic sections are the result …